23=3(2n-6)+3n

Solution for 23=3(2n-6)+3n equation:

23=3(2n-6)+3n

We move all terms to the left:

23-(3(2n-6)+3n)=0


We calculate terms in parentheses: -(3(2n-6)+3n), so:

3(2n-6)+3n

We add all the numbers together, and all the variables

3n+3(2n-6)

We multiply parentheses

3n+6n-18

We add all the numbers together, and all the variables

9n-18

Back to the equation:

-(9n-18)


We get rid of parentheses

-9n+18+23=0

We add all the numbers together, and all the variables

-9n+41=0

We move all terms containing n to the left, all other terms to the right

-9n=-41

n=-41/-9

n=4+5/9