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5(4x-9)-8=5(x-3)+52
We move all terms to the left:
5(4x-9)-8-(5(x-3)+52)=0
We multiply parentheses
20x-(5(x-3)+52)-45-8=0
We calculate terms in parentheses: -(5(x-3)+52), so:We add all the numbers together, and all the variables
5(x-3)+52
We multiply parentheses
5x-15+52
We add all the numbers together, and all the variables
5x+37
Back to the equation:
-(5x+37)
20x-(5x+37)-53=0
We get rid of parentheses
20x-5x-37-53=0
We add all the numbers together, and all the variables
15x-90=0
We move all terms containing x to the left, all other terms to the right
15x=90
x=90/15
x=6
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