2(3x-10)+20=8x+40

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Solution for 2(3x-10)+20=8x+40 equation: 



2(3x-10)+20=8x+40

We move all terms to the left:

2(3x-10)+20-(8x+40)=0

We multiply parentheses

6x-(8x+40)-20+20=0

We get rid of parentheses

6x-8x-40-20+20=0

We add all the numbers together, and all the variables

-2x-40=0

We move all terms containing x to the left, all other terms to the right

-2x=40

x=40/-2

x=-20

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