7(3b+2)+(22b-7)=0

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Solution for 7(3b+2)+(22b-7)=0 equation: 



7(3b+2)+(22b-7)=0

We multiply parentheses

21b+(22b-7)+14=0

We get rid of parentheses

21b+22b-7+14=0

We add all the numbers together, and all the variables

43b+7=0

We move all terms containing b to the left, all other terms to the right

43b=-7

b=-7/43

b=-7/43

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