(4y+6)-(2+3y)=11

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Solution for (4y+6)-(2+3y)=11 equation: 



(4y+6)-(2+3y)=11

We move all terms to the left:

(4y+6)-(2+3y)-(11)=0

We add all the numbers together, and all the variables

(4y+6)-(3y+2)-11=0

We get rid of parentheses

4y-3y+6-2-11=0

We add all the numbers together, and all the variables

y-7=0

We move all terms containing y to the left, all other terms to the right

y=7

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