7(2n+3)=9(4n+5)+8

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Solution for 7(2n+3)=9(4n+5)+8 equation: 



7(2n+3)=9(4n+5)+8

We move all terms to the left:

7(2n+3)-(9(4n+5)+8)=0

We multiply parentheses

14n-(9(4n+5)+8)+21=0



We calculate terms in parentheses: -(9(4n+5)+8), so:

9(4n+5)+8

We multiply parentheses

36n+45+8

We add all the numbers together, and all the variables

36n+53

Back to the equation:

-(36n+53)



We get rid of parentheses

14n-36n-53+21=0

We add all the numbers together, and all the variables

-22n-32=0

We move all terms containing n to the left, all other terms to the right

-22n=32

n=32/-22

n=-1+5/11

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