4/3x+1=5/4x

Solution for 4/3x+1=5/4x equation:

4/3x+1=5/4x

We move all terms to the left:

4/3x+1-(5/4x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

4/3x-(+5/4x)+1=0

We get rid of parentheses

4/3x-5/4x+1=0

We calculate fractions


16x/12x^2+(-15x)/12x^2+1=0

We multiply all the terms by the denominator


16x+(-15x)+1*12x^2=0

Wy multiply elements

12x^2+16x+(-15x)=0

We get rid of parentheses

12x^2+16x-15x=0

We add all the numbers together, and all the variables

12x^2+x=0

a = 12; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·12·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*12}=\frac{-2}{24}
=-1/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*12}=\frac{0}{24}
=0
$