7(2n+3)=7(4n+6)+8

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Solution for 7(2n+3)=7(4n+6)+8 equation: 



7(2n+3)=7(4n+6)+8

We move all terms to the left:

7(2n+3)-(7(4n+6)+8)=0

We multiply parentheses

14n-(7(4n+6)+8)+21=0



We calculate terms in parentheses: -(7(4n+6)+8), so:

7(4n+6)+8

We multiply parentheses

28n+42+8

We add all the numbers together, and all the variables

28n+50

Back to the equation:

-(28n+50)



We get rid of parentheses

14n-28n-50+21=0

We add all the numbers together, and all the variables

-14n-29=0

We move all terms containing n to the left, all other terms to the right

-14n=29

n=29/-14

n=-2+1/14

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