6y+-2(y+1)=3(y+2)+6

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Solution for 6y+-2(y+1)=3(y+2)+6 equation: 



6y+-2(y+1)=3(y+2)+6

We move all terms to the left:

6y+-2(y+1)-(3(y+2)+6)=0

We add all the numbers together, and all the variables

6y-2(y+1)-(3(y+2)+6)=0

We multiply parentheses

6y-2y-(3(y+2)+6)-2=0



We calculate terms in parentheses: -(3(y+2)+6), so:

3(y+2)+6

We multiply parentheses

3y+6+6

We add all the numbers together, and all the variables

3y+12

Back to the equation:

-(3y+12)



We add all the numbers together, and all the variables

4y-(3y+12)-2=0

We get rid of parentheses

4y-3y-12-2=0

We add all the numbers together, and all the variables

y-14=0

We move all terms containing y to the left, all other terms to the right

y=14

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