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4(2x+1)=3(3x+4)
We move all terms to the left:
4(2x+1)-(3(3x+4))=0
We multiply parentheses
8x-(3(3x+4))+4=0
We calculate terms in parentheses: -(3(3x+4)), so:We get rid of parentheses
3(3x+4)
We multiply parentheses
9x+12
Back to the equation:
-(9x+12)
8x-9x-12+4=0
We add all the numbers together, and all the variables
-1x-8=0
We move all terms containing x to the left, all other terms to the right
-x=8
x=8/-1
x=-8
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