44+4c+12=9c-41

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Solution for 44+4c+12=9c-41 equation: 



44+4c+12=9c-41

We move all terms to the left:

44+4c+12-(9c-41)=0

We add all the numbers together, and all the variables

4c-(9c-41)+56=0

We get rid of parentheses

4c-9c+41+56=0

We add all the numbers together, and all the variables

-5c+97=0

We move all terms containing c to the left, all other terms to the right

-5c=-97

c=-97/-5

c=19+2/5

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