1/2(2m-20)=1/4(20+8m)

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Solution for 1/2(2m-20)=1/4(20+8m) equation: 



1/2(2m-20)=1/4(20+8m)

We move all terms to the left:

1/2(2m-20)-(1/4(20+8m))=0



Domain of the equation: 2(2m-20)!=0

m∈R





Domain of the equation: 4(20+8m))!=0

m∈R



We add all the numbers together, and all the variables

1/2(2m-20)-(1/4(8m+20))=0

We calculate fractions


(4m8/(2(2m-20)*4(8m+20)))+(-2m2/(2(2m-20)*4(8m+20)))=0



We calculate terms in parentheses: +(4m8/(2(2m-20)*4(8m+20))), so:

4m8/(2(2m-20)*4(8m+20))

We multiply all the terms by the denominator


4m8

We add all the numbers together, and all the variables

4m^8

We do not support empression: m^8

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