6x2+5x=40

Solution for 6x2+5x=40 equation:

6x^2+5x=40

We move all terms to the left:

6x^2+5x-(40)=0

a = 6; b = 5; c = -40;
Δ = b2-4ac
Δ = 52-4·6·(-40)
Δ = 985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{985}}{2*6}=\frac{-5-\sqrt{985}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{985}}{2*6}=\frac{-5+\sqrt{985}}{12}
$