8x-1(7x+5)=-8-2(1x+12)

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Solution for 8x-1(7x+5)=-8-2(1x+12) equation: 



8x-1(7x+5)=-8-2(1x+12)

We move all terms to the left:

8x-1(7x+5)-(-8-2(1x+12))=0

We add all the numbers together, and all the variables

8x-1(7x+5)-(-8-2(x+12))=0



We calculate terms in parentheses: -(-8-2(x+12)), so:

-8-2(x+12)

determiningTheFunctionDomain
-2(x+12)-8

We multiply parentheses

-2x-24-8

We add all the numbers together, and all the variables

-2x-32

Back to the equation:

-(-2x-32)



We get rid of parentheses

8x-1(7x+5)+2x+32=0

We add all the numbers together, and all the variables

10x-1(7x+5)+32=0

We move all terms containing x to the left, all other terms to the right

10x-1(7x+5)=-32

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