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6/5x+3=-5/10x-3
We move all terms to the left:
6/5x+3-(-5/10x-3)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10x-3)!=0We get rid of parentheses
x∈R
6/5x+5/10x+3+3=0
We calculate fractions
60x/50x^2+25x/50x^2+3+3=0
We add all the numbers together, and all the variables
60x/50x^2+25x/50x^2+6=0
We multiply all the terms by the denominator
60x+25x+6*50x^2=0
We add all the numbers together, and all the variables
85x+6*50x^2=0
Wy multiply elements
300x^2+85x=0
a = 300; b = 85; c = 0;
Δ = b2-4ac
Δ = 852-4·300·0
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7225}=85$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(85)-85}{2*300}=\frac{-170}{600} =-17/60 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(85)+85}{2*300}=\frac{0}{600} =0 $
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