8x-1(7x+5)=-8-2(1x+12

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Solution for 8x-1(7x+5)=-8-2(1x+12 equation:



8x-1(7x+5)=-8-2(1x+12
We move all terms to the left:
8x-1(7x+5)-(-8-2(1x+12)=0
We add all the numbers together, and all the variables
8x-1(7x+5)-(-8-2(x+12)=0
We calculate terms in parentheses: -(-8-2(x+12), so:
-8-2(x+12
determiningTheFunctionDomain -2(x+12-8
Back to the equation:
-(-2(x+12-8)
We add all the numbers together, and all the variables
8x-1(7x+5)-(-2(x+4)=0
We calculate terms in parentheses: -(-2(x+4), so:
-2(x+4
We calculate terms in parentheses: -(-2(x+4), so:
-2(x+4
We calculate terms in parentheses: -(-2(x+4), so:
-2(x+4
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-2(x+4
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-2(x+4
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-2(x+4
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We calculate terms in parentheses: -(-2(x+4), so:
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We calculate terms in parentheses: -(-2(x+4), so:
-2(x+4
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-2(x+4
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-2(x+4
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-2(x+4
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-2(x+4
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-2(x+4
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-2(x+4
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