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5(4x+2)=-3(3x-5)
We move all terms to the left:
5(4x+2)-(-3(3x-5))=0
We multiply parentheses
20x-(-3(3x-5))+10=0
We calculate terms in parentheses: -(-3(3x-5)), so:We get rid of parentheses
-3(3x-5)
We multiply parentheses
-9x+15
Back to the equation:
-(-9x+15)
20x+9x-15+10=0
We add all the numbers together, and all the variables
29x-5=0
We move all terms containing x to the left, all other terms to the right
29x=5
x=5/29
x=5/29
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