6x2+3x-135=0

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Solution for 6x2+3x-135=0 equation:



6x^2+3x-135=0
a = 6; b = 3; c = -135;
Δ = b2-4ac
Δ = 32-4·6·(-135)
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-57}{2*6}=\frac{-60}{12} =-5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+57}{2*6}=\frac{54}{12} =4+1/2 $

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