6x(1x+10)=

Solution for 6x(1x+10)= equation:

6x(1x+10)=

We move all terms to the left:

6x(1x+10)-()=0

We add all the numbers together, and all the variables

6x(x+10)-()=0

We add all the numbers together, and all the variables

6x(x+10)=0

We multiply parentheses

6x^2+60x=0

a = 6; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·6·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*6}=\frac{-120}{12}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*6}=\frac{0}{12}
=0
$