63=3(4x+1)

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Solution for 63=3(4x+1) equation: 



63=3(4x+1)

We move all terms to the left:

63-(3(4x+1))=0



We calculate terms in parentheses: -(3(4x+1)), so:

3(4x+1)

We multiply parentheses

12x+3

Back to the equation:

-(12x+3)



We get rid of parentheses

-12x-3+63=0

We add all the numbers together, and all the variables

-12x+60=0

We move all terms containing x to the left, all other terms to the right

-12x=-60

x=-60/-12

x=+5

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