2(4x-2)-4(x-28)=5

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Solution for 2(4x-2)-4(x-28)=5 equation: 



2(4x-2)-4(x-28)=5

We move all terms to the left:

2(4x-2)-4(x-28)-(5)=0

We multiply parentheses

8x-4x-4+112-5=0

We add all the numbers together, and all the variables

4x+103=0

We move all terms containing x to the left, all other terms to the right

4x=-103

x=-103/4

x=-25+3/4

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