2b(b-1)=3(b-2)

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Solution for 2b(b-1)=3(b-2) equation: 



2b(b-1)=3(b-2)

We move all terms to the left:

2b(b-1)-(3(b-2))=0

We multiply parentheses

2b^2-2b-(3(b-2))=0



We calculate terms in parentheses: -(3(b-2)), so:

3(b-2)

We multiply parentheses

3b-6

Back to the equation:

-(3b-6)



We get rid of parentheses

2b^2-2b-3b+6=0

We add all the numbers together, and all the variables

2b^2-5b+6=0

a = 2; b = -5; c = +6;
Δ = b2-4ac
Δ = -52-4·2·6
Δ = -23
Delta is less than zero, so there is no solution for the equation

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