6/7-3/5(4x-9)=2/3x+8

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Solution for 6/7-3/5(4x-9)=2/3x+8 equation: 



6/7-3/5(4x-9)=2/3x+8

We move all terms to the left:

6/7-3/5(4x-9)-(2/3x+8)=0



Domain of the equation: 5(4x-9)!=0

x∈R





Domain of the equation: 3x+8)!=0

x∈R



We get rid of parentheses

-3/5(4x-9)-2/3x-8+6/7=0

We calculate fractions


(-441x)/(5(4x-9)*3x*7)+(-70x4/(5(4x-9)*3x*7)+(90x^24/(5(4x-9)*3x*7)-8=0



We calculate terms in parentheses: +(-441x)/(5(4x-9)*3x*7), so:

-441x)/(5(4x-9)*3x*7

We multiply all the terms by the denominator


-441x)

Back to the equation:

+(-441x))



We do not support expression: x^24

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