4(2x+4)=14-(x-2)

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Solution for 4(2x+4)=14-(x-2) equation: 



4(2x+4)=14-(x-2)

We move all terms to the left:

4(2x+4)-(14-(x-2))=0

We multiply parentheses

8x-(14-(x-2))+16=0



We calculate terms in parentheses: -(14-(x-2)), so:

14-(x-2)

determiningTheFunctionDomain
-(x-2)+14

We get rid of parentheses

-x+2+14

We add all the numbers together, and all the variables

-1x+16

Back to the equation:

-(-1x+16)



We get rid of parentheses

8x+1x-16+16=0

We add all the numbers together, and all the variables

9x=0

x=0/9

x=0

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