2/3(6x-12)+3(x+1)=35

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Solution for 2/3(6x-12)+3(x+1)=35 equation: 



2/3(6x-12)+3(x+1)=35

We move all terms to the left:

2/3(6x-12)+3(x+1)-(35)=0



Domain of the equation: 3(6x-12)!=0

x∈R



We multiply parentheses

2/3(6x-12)+3x+3-35=0

We multiply all the terms by the denominator


3x*3(6x-12)+3*3(6x-12)-35*3(6x-12)+2=0

Wy multiply elements

9x^2(6+9x(6-105x(6+2=0

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