(x-3)(x-3)=x(x-5)

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Solution for (x-3)(x-3)=x(x-5) equation: 



(x-3)(x-3)=x(x-5)

We move all terms to the left:

(x-3)(x-3)-(x(x-5))=0

We multiply parentheses ..

(+x^2-3x-3x+9)-(x(x-5))=0



We calculate terms in parentheses: -(x(x-5)), so:

x(x-5)

We multiply parentheses

x^2-5x

Back to the equation:

-(x^2-5x)



We get rid of parentheses

x^2-x^2-3x-3x+5x+9=0

We add all the numbers together, and all the variables

-1x+9=0

We move all terms containing x to the left, all other terms to the right

-x=-9

x=-9/-1

x=+9

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