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6(x+4)+6=9x-3(x-5)
We move all terms to the left:
6(x+4)+6-(9x-3(x-5))=0
We multiply parentheses
6x-(9x-3(x-5))+24+6=0
We calculate terms in parentheses: -(9x-3(x-5)), so:We add all the numbers together, and all the variables
9x-3(x-5)
We multiply parentheses
9x-3x+15
We add all the numbers together, and all the variables
6x+15
Back to the equation:
-(6x+15)
6x-(6x+15)+30=0
We get rid of parentheses
6x-6x-15+30=0
We add all the numbers together, and all the variables
15!=0
There is no solution for this equation
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