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3(x+6)(x+2)=-12
We move all terms to the left:
3(x+6)(x+2)-(-12)=0
We add all the numbers together, and all the variables
3(x+6)(x+2)+12=0
We multiply parentheses ..
3(+x^2+2x+6x+12)+12=0
We multiply parentheses
3x^2+6x+18x+36+12=0
We add all the numbers together, and all the variables
3x^2+24x+48=0
a = 3; b = 24; c = +48;
Δ = b2-4ac
Δ = 242-4·3·48
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-24}{6}=-4$
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