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8b=5/8((3b-4+b)4)
We move all terms to the left:
8b-(5/8((3b-4+b)4))=0
Domain of the equation: 8((3b-4+b)4))!=0We add all the numbers together, and all the variables
b∈R
8b-(5/8((4b-4)4))=0
We multiply all the terms by the denominator
8b*8((4b-4)4))-(5=0
Wy multiply elements
64b^2((=0
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