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/3I=I-22
We move all terms to the left:
/3I-(I-22)=0
Domain of the equation: 3I!=0We get rid of parentheses
I!=0/3
I!=0
I∈R
/3I-I+22=0
We multiply all the terms by the denominator
-I*3I+22*3I+=0
We add all the numbers together, and all the variables
-I*3I+22*3I=0
Wy multiply elements
-3I^2+66I=0
a = -3; b = 66; c = 0;
Δ = b2-4ac
Δ = 662-4·(-3)·0
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$I_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$I_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$I_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-66}{2*-3}=\frac{-132}{-6} =+22 $$I_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+66}{2*-3}=\frac{0}{-6} =0 $
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