6(x+3)=-7(2x-2)+8x

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Solution for 6(x+3)=-7(2x-2)+8x equation: 



6(x+3)=-7(2x-2)+8x

We move all terms to the left:

6(x+3)-(-7(2x-2)+8x)=0

We multiply parentheses

6x-(-7(2x-2)+8x)+18=0



We calculate terms in parentheses: -(-7(2x-2)+8x), so:

-7(2x-2)+8x

We add all the numbers together, and all the variables

8x-7(2x-2)

We multiply parentheses

8x-14x+14

We add all the numbers together, and all the variables

-6x+14

Back to the equation:

-(-6x+14)



We get rid of parentheses

6x+6x-14+18=0

We add all the numbers together, and all the variables

12x+4=0

We move all terms containing x to the left, all other terms to the right

12x=-4

x=-4/12

x=-1/3

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