22-(14-3x)=4+(9x-20)

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Solution for 22-(14-3x)=4+(9x-20) equation:



22-(14-3x)=4+(9x-20)
We move all terms to the left:
22-(14-3x)-(4+(9x-20))=0
We add all the numbers together, and all the variables
-(-3x+14)-(4+(9x-20))+22=0
We get rid of parentheses
3x-(4+(9x-20))-14+22=0
We calculate terms in parentheses: -(4+(9x-20)), so:
4+(9x-20)
determiningTheFunctionDomain (9x-20)+4
We get rid of parentheses
9x-20+4
We add all the numbers together, and all the variables
9x-16
Back to the equation:
-(9x-16)
We add all the numbers together, and all the variables
3x-(9x-16)+8=0
We get rid of parentheses
3x-9x+16+8=0
We add all the numbers together, and all the variables
-6x+24=0
We move all terms containing x to the left, all other terms to the right
-6x=-24
x=-24/-6
x=+4

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