2(x+3)=10-5(x-2)

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Solution for 2(x+3)=10-5(x-2) equation: 



2(x+3)=10-5(x-2)

We move all terms to the left:

2(x+3)-(10-5(x-2))=0

We multiply parentheses

2x-(10-5(x-2))+6=0



We calculate terms in parentheses: -(10-5(x-2)), so:

10-5(x-2)

determiningTheFunctionDomain
-5(x-2)+10

We multiply parentheses

-5x+10+10

We add all the numbers together, and all the variables

-5x+20

Back to the equation:

-(-5x+20)



We get rid of parentheses

2x+5x-20+6=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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