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7(x+1)=3(2x-3)+15
We move all terms to the left:
7(x+1)-(3(2x-3)+15)=0
We multiply parentheses
7x-(3(2x-3)+15)+7=0
We calculate terms in parentheses: -(3(2x-3)+15), so:We get rid of parentheses
3(2x-3)+15
We multiply parentheses
6x-9+15
We add all the numbers together, and all the variables
6x+6
Back to the equation:
-(6x+6)
7x-6x-6+7=0
We add all the numbers together, and all the variables
x+1=0
We move all terms containing x to the left, all other terms to the right
x=-1
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