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(2x-1)(4x=1)
We move all terms to the left:
(2x-1)(4x-(1))=0
We multiply parentheses ..
(+8x^2-2x-4x+1)=0
We get rid of parentheses
8x^2-2x-4x+1=0
We add all the numbers together, and all the variables
8x^2-6x+1=0
a = 8; b = -6; c = +1;
Δ = b2-4ac
Δ = -62-4·8·1
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2}{2*8}=\frac{4}{16} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2}{2*8}=\frac{8}{16} =1/2 $
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