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6(x+2)=5/4x
We move all terms to the left:
6(x+2)-(5/4x)=0
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
6(x+2)-(+5/4x)=0
We multiply parentheses
6x-(+5/4x)+12=0
We get rid of parentheses
6x-5/4x+12=0
We multiply all the terms by the denominator
6x*4x+12*4x-5=0
Wy multiply elements
24x^2+48x-5=0
a = 24; b = 48; c = -5;
Δ = b2-4ac
Δ = 482-4·24·(-5)
Δ = 2784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2784}=\sqrt{16*174}=\sqrt{16}*\sqrt{174}=4\sqrt{174}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-4\sqrt{174}}{2*24}=\frac{-48-4\sqrt{174}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+4\sqrt{174}}{2*24}=\frac{-48+4\sqrt{174}}{48} $
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