6(2t-3)=-2(t+7)-4

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Solution for 6(2t-3)=-2(t+7)-4 equation: 



6(2t-3)=-2(t+7)-4

We move all terms to the left:

6(2t-3)-(-2(t+7)-4)=0

We multiply parentheses

12t-(-2(t+7)-4)-18=0



We calculate terms in parentheses: -(-2(t+7)-4), so:

-2(t+7)-4

We multiply parentheses

-2t-14-4

We add all the numbers together, and all the variables

-2t-18

Back to the equation:

-(-2t-18)



We get rid of parentheses

12t+2t+18-18=0

We add all the numbers together, and all the variables

14t=0

t=0/14

t=0

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