6(2t-3)=-2(t+7)-3

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Solution for 6(2t-3)=-2(t+7)-3 equation: 



6(2t-3)=-2(t+7)-3

We move all terms to the left:

6(2t-3)-(-2(t+7)-3)=0

We multiply parentheses

12t-(-2(t+7)-3)-18=0



We calculate terms in parentheses: -(-2(t+7)-3), so:

-2(t+7)-3

We multiply parentheses

-2t-14-3

We add all the numbers together, and all the variables

-2t-17

Back to the equation:

-(-2t-17)



We get rid of parentheses

12t+2t+17-18=0

We add all the numbers together, and all the variables

14t-1=0

We move all terms containing t to the left, all other terms to the right

14t=1

t=1/14

t=1/14

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