3(m-3)=6(m+2)-6

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Solution for 3(m-3)=6(m+2)-6 equation: 



3(m-3)=6(m+2)-6

We move all terms to the left:

3(m-3)-(6(m+2)-6)=0

We multiply parentheses

3m-(6(m+2)-6)-9=0



We calculate terms in parentheses: -(6(m+2)-6), so:

6(m+2)-6

We multiply parentheses

6m+12-6

We add all the numbers together, and all the variables

6m+6

Back to the equation:

-(6m+6)



We get rid of parentheses

3m-6m-6-9=0

We add all the numbers together, and all the variables

-3m-15=0

We move all terms containing m to the left, all other terms to the right

-3m=15

m=15/-3

m=-5

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