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6(x+2)=4(3-2x)
We move all terms to the left:
6(x+2)-(4(3-2x))=0
We add all the numbers together, and all the variables
6(x+2)-(4(-2x+3))=0
We multiply parentheses
6x-(4(-2x+3))+12=0
We calculate terms in parentheses: -(4(-2x+3)), so:We get rid of parentheses
4(-2x+3)
We multiply parentheses
-8x+12
Back to the equation:
-(-8x+12)
6x+8x-12+12=0
We add all the numbers together, and all the variables
14x=0
x=0/14
x=0
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