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6(3x-2)=4(2x-3)
We move all terms to the left:
6(3x-2)-(4(2x-3))=0
We multiply parentheses
18x-(4(2x-3))-12=0
We calculate terms in parentheses: -(4(2x-3)), so:We get rid of parentheses
4(2x-3)
We multiply parentheses
8x-12
Back to the equation:
-(8x-12)
18x-8x+12-12=0
We add all the numbers together, and all the variables
10x=0
x=0/10
x=0
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