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/3x+11=3x-11
We move all terms to the left:
/3x+11-(3x-11)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
/3x-3x+11+11=0
We multiply all the terms by the denominator
-3x*3x+11*3x+11*3x+=0
We add all the numbers together, and all the variables
-3x*3x+11*3x+11*3x=0
Wy multiply elements
-9x^2+33x+33x=0
We add all the numbers together, and all the variables
-9x^2+66x=0
a = -9; b = 66; c = 0;
Δ = b2-4ac
Δ = 662-4·(-9)·0
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-66}{2*-9}=\frac{-132}{-18} =7+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+66}{2*-9}=\frac{0}{-18} =0 $
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