(3k-2)(2k-1)=k(6k+5)-3

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Solution for (3k-2)(2k-1)=k(6k+5)-3 equation: 



(3k-2)(2k-1)=k(6k+5)-3

We move all terms to the left:

(3k-2)(2k-1)-(k(6k+5)-3)=0

We multiply parentheses ..

(+6k^2-3k-4k+2)-(k(6k+5)-3)=0



We calculate terms in parentheses: -(k(6k+5)-3), so:

k(6k+5)-3

We multiply parentheses

6k^2+5k-3

Back to the equation:

-(6k^2+5k-3)



We get rid of parentheses

6k^2-6k^2-3k-4k-5k+2+3=0

We add all the numbers together, and all the variables

-12k+5=0

We move all terms containing k to the left, all other terms to the right

-12k=-5

k=-5/-12

k=5/12

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