-2(2-x2)=4-8(1-x)=

Solution for -2(2-x2)=4-8(1-x)= equation:

-2(2-x2)=4-8(1-x)=

We move all terms to the left:

-2(2-x2)-(4-8(1-x))=0

We add all the numbers together, and all the variables

-2(-1x^2+2)-(4-8(-1x+1))=0

We multiply parentheses

2x^2-(4-8(-1x+1))-4=0


We calculate terms in parentheses: -(4-8(-1x+1)), so:

4-8(-1x+1)

determiningTheFunctionDomain
-8(-1x+1)+4

We multiply parentheses

8x-8+4

We add all the numbers together, and all the variables

8x-4

Back to the equation:

-(8x-4)


We get rid of parentheses

2x^2-8x+4-4=0

We add all the numbers together, and all the variables

2x^2-8x=0

a = 2; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·2·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*2}=\frac{16}{4}
=4
$