6(v-1)-7=-4(-6v+2)-8v

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Solution for 6(v-1)-7=-4(-6v+2)-8v equation:



6(v-1)-7=-4(-6v+2)-8v
We move all terms to the left:
6(v-1)-7-(-4(-6v+2)-8v)=0
We multiply parentheses
6v-(-4(-6v+2)-8v)-6-7=0
We calculate terms in parentheses: -(-4(-6v+2)-8v), so:
-4(-6v+2)-8v
We add all the numbers together, and all the variables
-8v-4(-6v+2)
We multiply parentheses
-8v+24v-8
We add all the numbers together, and all the variables
16v-8
Back to the equation:
-(16v-8)
We add all the numbers together, and all the variables
6v-(16v-8)-13=0
We get rid of parentheses
6v-16v+8-13=0
We add all the numbers together, and all the variables
-10v-5=0
We move all terms containing v to the left, all other terms to the right
-10v=5
v=5/-10
v=-1/2

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