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3(3x+9)-2=5(2x-3)
We move all terms to the left:
3(3x+9)-2-(5(2x-3))=0
We multiply parentheses
9x-(5(2x-3))+27-2=0
We calculate terms in parentheses: -(5(2x-3)), so:We add all the numbers together, and all the variables
5(2x-3)
We multiply parentheses
10x-15
Back to the equation:
-(10x-15)
9x-(10x-15)+25=0
We get rid of parentheses
9x-10x+15+25=0
We add all the numbers together, and all the variables
-1x+40=0
We move all terms containing x to the left, all other terms to the right
-x=-40
x=-40/-1
x=+40
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