-3(y-3)+2y=4(-2y-3)

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Solution for -3(y-3)+2y=4(-2y-3) equation: 



-3(y-3)+2y=4(-2y-3)

We move all terms to the left:

-3(y-3)+2y-(4(-2y-3))=0

We add all the numbers together, and all the variables

2y-3(y-3)-(4(-2y-3))=0

We multiply parentheses

2y-3y-(4(-2y-3))+9=0



We calculate terms in parentheses: -(4(-2y-3)), so:

4(-2y-3)

We multiply parentheses

-8y-12

Back to the equation:

-(-8y-12)



We add all the numbers together, and all the variables

-1y-(-8y-12)+9=0

We get rid of parentheses

-1y+8y+12+9=0

We add all the numbers together, and all the variables

7y+21=0

We move all terms containing y to the left, all other terms to the right

7y=-21

y=-21/7

y=-3

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