6(r+2)=3(2r+4)

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Solution for 6(r+2)=3(2r+4) equation: 



6(r+2)=3(2r+4)

We move all terms to the left:

6(r+2)-(3(2r+4))=0

We multiply parentheses

6r-(3(2r+4))+12=0



We calculate terms in parentheses: -(3(2r+4)), so:

3(2r+4)

We multiply parentheses

6r+12

Back to the equation:

-(6r+12)



We get rid of parentheses

6r-6r-12+12=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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