10x2+3x-1=0

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Solution for 10x2+3x-1=0 equation:



10x^2+3x-1=0
a = 10; b = 3; c = -1;
Δ = b2-4ac
Δ = 32-4·10·(-1)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-7}{2*10}=\frac{-10}{20} =-1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+7}{2*10}=\frac{4}{20} =1/5 $

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