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4(3x-5)=2(6x-10)+3
We move all terms to the left:
4(3x-5)-(2(6x-10)+3)=0
We multiply parentheses
12x-(2(6x-10)+3)-20=0
We calculate terms in parentheses: -(2(6x-10)+3), so:We get rid of parentheses
2(6x-10)+3
We multiply parentheses
12x-20+3
We add all the numbers together, and all the variables
12x-17
Back to the equation:
-(12x-17)
12x-12x+17-20=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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